Möbius Transformation 莫比乌斯变换

中文English
莫比乌斯变换Möbius Transformation / Fractional Linear Transformation
变换行列式Determinant:Δ=ad−bc(核心判别式)
非退化Non-degenerate
退化Degenerate

标准表达式

\(\boldsymbol{f(x)=\frac{ax+b}{cx+d}},\quad a,b,c,d\in\mathbb{R}\)

When \(\boldsymbol{\Delta=ad-bc \neq 0}\), the linear polynomials \(ax+b\) and \(cx+d\) are linearly independent, not scalar multiples of each other. The function cannot reduce to a constant; its graph is a hyperbola, a bijection with another Möbius transformation as its inverse.

\(\boldsymbol{\Delta=ad-bc=0}\) means coefficient vectors \((a,b)\) and \((c,d)\) are linearly dependent, so there exists a constant k such that \(a=kc,\;b=kd\). Substitute into the rational function: \(f(x)=\frac{k(cx+d)}{cx+d}=k\) The expression collapses into a constant horizontal line \(y=k\). It loses all features of a Möbius transformation → degenerate case.

行列式不等于 0,一次多项式 \(ax+b\) 和 \(cx+d\) 线性无关、不成正比例,无法约分消去分母。

函数图像是双曲线,是双射函数,存在同类型分式形式的反函数,是标准有效的莫比乌斯变换。

只有这类非退化双曲线才有可能图像关于 \(y=x\) 对称。

\(a=1,d=-1 \Rightarrow bc=-1\),取 \(b=1,c=-1\): \(y=\frac{x+1}{-x-1}=-1\)

degenerate to horizontal line (y=-1), invalid for the problem.

2024 AMC 12A Problems/Problem 25


A graph is $\textit{symmetric}$ about a line if the graph remains unchanged after reflection in that line. For how many quadruples of integers $(a,b,c,d)$, where $|a|,|b|,|c|,|d|\le5$ and $c$ and $d$ are not both $0$, is the graph of\[y=\frac{ax+b}{cx+d}\]symmetric about the line $y=x$?

$\textbf{(A) }1282\qquad\textbf{(B) }1292\qquad\textbf{(C) }1310\qquad\textbf{(D) }1320\qquad\textbf{(E) }1330$

普通概率计算容易得到1320,但是需要减去各种退化的情况

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