| 中文 | English |
|---|---|
| 莫比乌斯变换 | Möbius Transformation / Fractional Linear Transformation |
| 变换行列式 | Determinant:Δ=ad−bc(核心判别式) |
| 非退化 | Non-degenerate |
| 退化 | Degenerate |
标准表达式
\(\boldsymbol{f(x)=\frac{ax+b}{cx+d}},\quad a,b,c,d\in\mathbb{R}\)
When \(\boldsymbol{\Delta=ad-bc \neq 0}\), the linear polynomials \(ax+b\) and \(cx+d\) are linearly independent, not scalar multiples of each other. The function cannot reduce to a constant; its graph is a hyperbola, a bijection with another Möbius transformation as its inverse.
\(\boldsymbol{\Delta=ad-bc=0}\) means coefficient vectors \((a,b)\) and \((c,d)\) are linearly dependent, so there exists a constant k such that \(a=kc,\;b=kd\). Substitute into the rational function: \(f(x)=\frac{k(cx+d)}{cx+d}=k\) The expression collapses into a constant horizontal line \(y=k\). It loses all features of a Möbius transformation → degenerate case.
行列式不等于 0,一次多项式 \(ax+b\) 和 \(cx+d\) 线性无关、不成正比例,无法约分消去分母。
函数图像是双曲线,是双射函数,存在同类型分式形式的反函数,是标准有效的莫比乌斯变换。
只有这类非退化双曲线才有可能图像关于 \(y=x\) 对称。
\(a=1,d=-1 \Rightarrow bc=-1\),取 \(b=1,c=-1\): \(y=\frac{x+1}{-x-1}=-1\)
degenerate to horizontal line (y=-1), invalid for the problem.
2024 AMC 12A Problems/Problem 25
A graph is
about a line if the graph remains unchanged after reflection in that line. For how many quadruples of integers
, where
and
and
are not both
, is the graph of
symmetric about the line
?

普通概率计算容易得到1320,但是需要减去各种退化的情况
Leave a Reply
You must be logged in to post a comment.